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Investigating Forces & Motion
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Investigating Forces and Motion (1998)(Granada Learning).iso
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topic1
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1998-02-10
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349 lines
[question1]
type:2
caption:\
A footballer shoots 15 m from the goal. If the ball travels at an \
average speed of 30 m/s, how long does the goalkeeper have to make a \
save?<p>
correct:0.5 s
wrong1:2.0 s
wrong2:1.0 s
wrong3:0.1 s
feedback:\
<img src="sa1q1a" align=center><p>\
so,<p>\
<img src="sa1q1b" align=center><p>\
<img src="sa1q1c" align=center><p>\
<center>= 0.5 s.</center><p>
[question2]
type:2
caption:\
A drag-racing car takes 6.0 s to cover a 400 m course from a standing \
start. If the car is travelling at 132 m/s as it crosses the finish \
line, what is its average acceleration for the whole race?<p>
correct:22 m/s<sup>2</sup>
wrong1:132 m/s<sup>2</sup>
wrong2:67 m/s<sup>2</sup>
wrong3:30 m/s<sup>2</sup>
feedback:\
<img src="sa1q2a" align=center><p>\
<img src="sa1q2b" align=center><p>\
<center>= 22 m/s<sup>2</sup>.</center><p>
[question3]
type:1
image:1g10
caption:\
A person carrying a dripping bucket walks across a floor covered with \
1.0 m square tiles. You can see the pattern left by the drips. If the \
bucket was dripping at a constant rate of two drips per second, how \
fast was the person walking?<p>
correct:1.5 m/s
wrong1:0.5 m/s
wrong2:1.0 m/s
wrong3:3.0 m/s
feedback:\
Two drips per second means that the time interval between drips is 0.5 \
s. The distance between drips is 0.75 m, therefore,<p>\
<img src="sa1q1a" align=center><p>\
<img src="sa1q3a" align=center><p>\
<center>= 1.5 m/s.</center><p>
[question4]
type:1
image:1g11
caption:\
This series of photographs shows a rabbit accelerating from a standing \
start against a background grid. If the photographs were recorded at \
0.5 s intervals, what was the rabbit's acceleration?<p>
correct:4.0 m/s<sup>2</sup>
wrong1:1.0 m/s<sup>2</sup>
wrong2:2.0 m/s<sup>2</sup>
wrong3:3.0 m/s<sup>2</sup>
feedback:\
In the first 0.5 s interval, the rabbit travels 1.0 m. The rabbit's \
average speed is therefore <img src="sa1q4a" align=center><p>\
The rabbit travels 2.0 m in the next 0.5 s, so its average speed is \
therefore<p>\
<img src="sa1q4b" align=center><p>\
<img src="sa1q2a" align=center><p>\
<img src="sa1q4c" align=center><p>\
<center>= 4.0 m/s<SUP>2</SUP>.</center><p>
[question5]
type:2
caption:\
A car makes a journey of 30 km in 20 minutes. What was its average \
speed in metres per second?<p>
correct:25 m/s
wrong1:1.5 m/s
wrong2:2.0 m/s
wrong3:15 m/s
feedback:\
To calculate the correct answer, you must first convert kilometres to \
metres and minutes to seconds:<p>\
30 km = 30 x 1 000 m<p>\
20 minutes = 20 x 60 s<p>\
Then calculate the car's average speed using the following \
equation:<p>\
<img src="sa1q5a" align=center><p>\
<img src="sa1q5b" align=center><p>\
<center>= 25 m/s.</center><p>
[question6]
type:2
caption:\
What is the average velocity of an athlete who completes one lap of a \
400 m track and returns to the starting line in 50 s?<p>
correct:0.0 m/s
wrong1:4.0 m/s
wrong2:8.0 m/s
wrong3:20 m/s
feedback:\
<img src="sa1q6a" align=center><p>\
Velocity is a vector quantity; it can be negative as well as positive. \
As the track is circled, the athlete's velocity changes direction. On \
one side of the track it is positive, but on the other side it is \
negative, so the average velocity for a complete lap is 0.0 m/s.<p>\
To put it another way, when the athlete returns to the starting point, \
displacement is 0.0 m. Using the above equation, we find that: <img \
src="sa1q6b" align=center><p>
[question7]
type:2
caption:\
What is the average speed of an athlete who completes one lap of a 400 \
m track and returns to the starting line in 50 s?<p>
correct:8.0 m/s
wrong1:0.0 m/s
wrong2:4.0 m/s
wrong3:20 m/s
feedback:\
Speed does not have a direction, so the athlete's speed is always \
positive. We can calculate the athlete's speed with the equation:<p>\
<img src="sa1q1a" align=center><p>\
<img src="sa1q7a" align=center><p>\
<center>= 8.0 m/s.</center><p>
[question8]
type:2
caption:What are the units of acceleration?<p>
correct:m/s<sup>2</sup>
wrong1:ms<sup>2</sup>
wrong2:ms
wrong3:m/s
feedback:\
Acceleration is equal to the change in velocity divided by the time it \
takes for the change to occur. The units of velocity are metres per \
second (m/s), so the units of acceleration are metres per second per \
second, or m/s<sup>2</sup>.<p>
[question9]
type:2
caption:\
A rocket is launched from rest with an acceleration of 5.0 \
m/s<sup>2</sup>. What is its speed after 10 seconds?<p>
correct:50 m/s
wrong1:20 m/s
wrong2:5.0 m/s
wrong3:2.0 m/s
feedback:\
Because the rocket is accelerating in a straight line, its speed \
change is the same as its velocity change.<p>\
<img src="sa1q9a" align=center><p>\
so,<p>\
velocity change = acceleration x time<p>\
<center>= 5.0 x 10</center><p>\
<center>= 50 m/s.</center><p>
[question10]
type:1
image:1g12
caption:\
The tracks below are the fossilised footprints of a dinosaur running \
on its hind legs. Tests on this species' skeleton show that it could \
probably have taken one stride every 0.5 s. How fast was this dinosaur \
running?<p>
correct:10 m/s
wrong1:2.0 m/s
wrong2:5.0 m/s
wrong3:20 m/s
feedback:\
The distance between footprints is 5.0 m.<p>\
<img src="sa1q1a" align=center><p>\
<img src="sa1q10a" align=center><p>\
<center>= 10 m/s.</center><p>
[question11]
type:2
caption:\
A rocket must reach a speed of 8 400 m/s to get into orbit around the \
Earth. If it is launched from rest and enters orbit 2.0 minutes later, \
what is its average acceleration?<p>
correct:70 m/s<sup>2</sup>
wrong1:2.0 m/s<sup>2</sup>
wrong2:8.4 m/s<sup>2</sup>
wrong3:4 200 m/s<sup>2</sup>
feedback:\
<img src="sa1q9a" align=center><p>\
<img src="sa1q11a" align=center><p>\
<center>= 70 m/s<sup>2</sup>.</center><p>
[question12]
type:1
image:1g13
caption:\
A child on a fishing boat is throwing fish heads over the side at the \
rate of one every 5.0 s. The pattern of splashes behind the boat is \
shown on the diagram. Which graph shows how the boat's velocity is \
changing?<p>
correct:Graph A
wrong1:Graph B
wrong2:Graph C
wrong3:Graph D
feedback:\
The splashes are getting closer together at a steady rate, showing \
that the boat is slowing down with a uniform negative acceleration.<p>
[question13]
type:2
caption:\
A moving car starts accelerating along a straight road. During the \
first second it travels 20 m. During the next second it travels 24 m. \
What is the car's acceleration?<p>
correct:4.0 m/s<sup>2</sup>
wrong1:8.0 m/s<sup>2</sup>
wrong2:24 m/s<sup>2</sup>
wrong3:20 m/s<sup>2</sup>
feedback:\
<img src="sa1q1a" align=center><p>\
<img src="sa1q9a" align=center><p>\
The speed in the first second = <img src="sa1q13a"> = 20 m/s<p>\
The speed in the second second = <img src="sa1q13b"> = 24 m/s<p>\
Because the acceleration is in a straight line, the speed change \
equals the velocity change.<p>\
<img src="sa1q13c" align=center><p>
[question14]
type:2
caption:\
A cyclist travelling at 10.0 m/s brakes sharply and comes to rest in \
2.5 s. What is the cyclist's acceleration?<p>
correct:-4.0 m/s<sup>2</sup>
wrong1:4.0 m/s<sup>2</sup>
wrong2:7.5 m/s<sup>2</sup>
wrong3:-7.5 m/s<sup>2</sup>
feedback:\
<img src="sa1q9a" align=center><p>\
<img src="sa1q14a" align=center><p>\
<img src="sa1q14b" align=center><p>\
<center>= -4.0 m/s<sup>2</sup>.</center><p>
[question15]
type:1
image:1g14
caption:\
A ticker-tape timer makes one dot every 0.02 s. What is the speed of \
the truck that pulled this tape through the timer?<p>
correct:1.5 m/s
wrong1:0.5 m/s
wrong2:1.0 m/s
wrong3:2.0 m/s
feedback:\
The distance between consecutive dots is 3.0 cm.<p>\
<img src="sa1q1a" align=center><p>\
<img src="sa1q15a" align=center><p>\
<center>= 150 cm/s = 1.5 m/s.</center><p>
[question16]
type:1
image:1g15
caption:\
A ticker-tape timer makes one dot every 0.02 s. What is the \
acceleration of the truck that pulled this tape through the timer?<p>
correct:12.5 m/s<sup>2</sup>
wrong1:2.5 m/s<sup>2</sup>
wrong2:5.0 m/s<sup>2</sup>
wrong3:25 m/s<sup>2</sup>
feedback:\
The distance between dots increases by 0.5 cm every 0.02 seconds. This \
means that the velocity increases by 0.5 ÷ 0.02 = 25 cm/s every \
0.02 s.<p>\
<img src="sa1q9a" align=center><p>\
<img src="sa1q16a" align=center><p>\
<center>= 1 250 cm/s<sup>2</sup> = 12.5 m/s<sup>2</sup>.</center><p>
[question17]
type:2
caption:\
A boat decelerates in a straight line with a uniform acceleration of \
-0.5 m/s<sup>2</sup>. If its initial speed was 2.5 m/s, how many \
seconds is it until the boat comes to a standstill?<p>
correct:5.0 s
wrong1:2.0 s
wrong2:3.0 s
wrong3:4.0 s
feedback:\
speed change = final speed - initial speed<p>\
<center>= 0.0 - 2.5 = -2.5 m/s</center><p>\
Because the boat is slowing down in a straight line, its velocity \
change is equal to its speed change.<p>\
<img src="sa1q9a" align=center><p>\
so,<p>\
<img src="sa1q17a" align=center><p>\
<center>= -2.5/-0.5 = 5.0 s.</center><p>
[question18]
type:1
image:1g16
caption:\
Water is dripping from a tank behind a tractor at the rate of one drip \
per second. The diagram shows the pattern of drips as the tractor \
drives along a paved road. What is the tractor's acceleration?<p>
correct:-0.1 m/s<sup>2</sup>
wrong1:0.0 m/s<sup>2</sup>
wrong2:0.1 m/s<sup>2</sup>
wrong3:-0.2 m/s<sup>2</sup>
feedback:\
The distance between drips decreases by 0.1 m every second. This means \
that the velocity changes by -0.1 ÷ 1.0 = -0.1 m/s every \
second.<p>\
<img src="sa1q9a" align=center><p>\
<img src="sa1q18a" align=center><p>\
<center>= -0.1 m/s<sup>2</sup>.</center><p>
[question19]
type:2
caption:\
How long does it take a car to make a journey of 20 km if it is \
travelling at an average speed of 50 km/h?<p>
correct:24 minutes
wrong1:20 minutes
wrong2:30 minutes
wrong3:50 minutes
feedback:\
<img src="sa1q1a" align=center><p>\
so,<p>\
<img src="sa1q1b" align=center><p>\
<img src="sa1q19a" align=center><p>\
<center>= 0.4 hour = 24 minutes.</center><p>
[question20]
type:2
caption:\
If a falling stone has an acceleration of 10 m/s<sup>2</sup>, what is \
its speed when it has been falling from rest in a straight line for \
4.0 seconds?<p>
correct:40 m/s
wrong1:20 m/s
wrong2:4.0 m/s
wrong3:2.5 m/s
feedback:\
<img src="sa1q9a" align=center><p>\
so,<p>\
velocity change = acceleration x time<p>\
<center>= 10 x 4.0 = 40 m/s</center><p>\
Because the stone is falling in a straight line from rest, its speed \
change will equal its velocity change.<p>